6x^2-29x+34=0

Solution for 6x^2-29x+34=0 equation:

6x^2-29x+34=0

a = 6; b = -29; c = +34;
Δ = b2-4ac
Δ = -292-4·6·34
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-5}{2*6}=\frac{24}{12}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+5}{2*6}=\frac{34}{12}
=2+5/6
$